In a quadrilateral ABCD, AO and BO are the bisectors of `angleA and angleB` respectively. Prove that `angleAOB=1/2(angleC+angleD).`

In a quadrilateral ABCD, AO and BO are bisectors of angleA and angle B respectively. Prove that angleAOB=1/2(angleC+angleD)

In a quadrilateral ABCD, AO and BO are bisector of angle A and angle B resepectively. Sho that : angleAOB=1/2 (angleC+angleD)

In a quadrilateral ABCD,AO and BO are the bisectors of A/_ and /_B respectively. Prove that /_AOB=(1)/(2)(/_C+/_D)

In quadrilateral ABCD,AO and BO are the bisectors of /_A and /_B respectively.Prove that /_AOB=(1)/(2)(/_C+/_D)

In a quadrilateral ABCD, AO and BO are the bisectors of angle A and angle B respectively, angle C = 70^(@) and angle D=30^(@). " Then, " angle AOB= ?

In quadrilateral ABCD, AP and BP are bisector of angleA and angleB respectively, then find the value of x

In the adjoining figure, ABCD is a parallelogram , AO and BO are the bisectors of angleA and angleB respectively. Prove that angleAOB=90^@ .

In a quadrilateral ABCD, if AO and BO are the bisectors angleA and angleB respectively, angleC=70^@ and angleD=30^@ then angleAOB =

In the given figure, ABgtAC. If BO and CO are the bisectors of angleB and angleC respectively then

If a quadrilateral ABCD, the bisector of angleC & angleD intersect at O. Prove that angleCOD=(1)/(2)(angleA+angleB)