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A radioactive element A of decay constan...

A radioactive element A of decay constant `lamda_(A)` decays into another radioactive element B of decay constant `lamda_(B)`. Initially the number of active nuclei of A was `N_(0)` and B was absent in the sample. The maximum number of active nuclei of B is found at t=2. In `2//lamda_(A)`. The maximum number of active nuclei of B is

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A parent radioactive nucleus A (decay constant lamda_(A)) converts into a radio-active nucleus B of decay constant lamda_(b) , initially, number of atoms of B is zero At any time N_(a),N_(b) are number of atoms of nuclei A and B respectively then maximum velue of N_(b) .

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