When F = 2n, the frictional force between 10 kg block 5 kg block is

When F = 2N, the frictional force between 5 kg block and ground is

When F = 2N, the frictional force between 5 kg block and ground is

When F = 2N, the frictional force between 5 kg block and ground is

In the shown arrangements if f_(1), f_(2) and T be the frictional forces on 2 kg block, 3 kg block & tension in the string respectively, then their values are

In the shown arrangements if f_(1), f_(2) and T be the frictional forces on 2 kg block, 3 kg block & tension in the string respectively, then their values are

In the shown arrangement if f_(1),f_(2) and T be the frictional forces on 2 kg block, 3 kg block & tension in the string respectively, then their values are:

A block of mass 2kg is kept on the floor. The coefficient of static friction is 0.4 . If a force F of 2.5N is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

A block of mass 2kg is kept on the floor. The coefficient of static friction is 0.4 . If a force F of 2.5N is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

Two blocks of masses 2 kg and 4kg are connected through a massless inextensible string. The co-efficient of fricition between 2kg block and ground is 0.4 and the coefficient of friction between 4kg block and ground is 0.6. The forces F_(1)=10N and F_(2)=20N are applied on the blocks as shown in the figure. Calculate the frictional force between 4 kg block and ground (Assume initially the tension in the string was just before forces F_(1) and F_(2) wer applied).