A force of one newton doubles the length of a cord having cross-sectional area `1mrh^(2)`. The Young's modulus of the material of the cord is

COMPLETION TYPE QUESTIONS A tensile force of 2 xx 10^5 dyne doubles the length of an elastic cord whose area of cross-section is 2 cm^2 . The Young's modulus of the material of the cord is _______.

Calculate the force required to incrase the length of wire of cross-sectional area 10^(-6) m^(2) by 50% if the Young's modulus of the material of the wire is 90 xx 10^(9) Pa .

Work done in stretching a wire of length 1 m and of cross-sectional area 1 mm^(2) through 2 mm if Young's modulus of the material of the wire is 2 xx 10 ^(11) N//m^(2) is .......

A force F doubles the length of wire of cross-section a The Young modulus of wire is

A force F doubles the length of wire of cross-section a The Young modulus of wire is

A force of 100 N produces a change of 0.01% in a length of wire of area of cross -section 1.0 mm^2 . Young's modulus of the wire is

A wire of 10m long and 1mm^(2) area of cross section is strechted by a force of 20N . If the elongation is 2mm the young's modulus of the material of the wire (in Pa ) is

A wire length L and cross sectional area A is made of material of Young's modulus Y . It is strectched by an amount X . The work done is

A wire of length L and area of cross-section A, is stretched by a load. The elongation produced in the wire is I. If Y is the Young's modulus of the material of the wire, then the force constant of the wire is