The structural formula of a compound is `CH_(3)-CH=C=CH_(2)`. The type of hybridization at the four carbons from left to right are

The structural formula of a compound is CH_3 - CH = C = CH_2 . The type of hybridisation at the four carbon atoms from left to right:

In the compound CH_(3) - CH = C = CH - CH_(3) , hybridization of C_(2) and C_(3) carbons respectively are -

Draw structural formula of compound from A to F . CH_(3) - CH = CH - C_(6) H_(5) + HOCl to B

In the compound HC-=C-CH=CH_2 , the hybridizations of C-2 and C-3 carbons are, respectively,

CH_(3)-CH=CH-CH_(2)C-=CH In the above compounds the hybridization of "1,3,5" carbon atoms is

Write the structural formula of a compound of molecular formula C_(4)H_(8)Cl_(2) in which (a) all the carbon atoms are involved in -CH_(2) groups (b) none of the carbon atoms is involved in -CH_(2) group.

Write the structural formula of a compound of molecular formula C_(4)H_(8)Cl_(2) in which (a) all the carbon atoms are involved in -CH_(2) groups (b) none of the carbon atoms is involved in -CH_(2) group.

Write the structural formula of a compound of molecular formula C_(4)H_(8)Cl_(2) in which (a) all the carbon atoms are involved in -CH_(2) groups (b) none of the carbon atoms is involved in -CH_(2) group.

CH_(3)-CH=CH-CH_(2)C-=CH In the above compounds thehybridization of "1,3,5" carbon atoms is

In the hydrocarbon CH_(3)-CH = CH-CH_(2) -C = CH The state of hybridization of carbons 1,3 and 5 are in the following sequence