The potential energy `varphi`, in joule, of a particle of mass `1kg`, moving in the x-y plane, obeys the law `varphi=3x+4y`, where `(x,y)` are the coordinates of the particle in metre. If the particle is at rest at `(6,4)` at time `t=0`, then

The potential energy U in joule of a particle of mass 1 kg moving in x-y plane obeys the law U = 3x + 4y , where (x,y) are the co-ordinates of the particle in metre. If the particle is at rest at (6,4) at time t = 0 then :

The potential energy U in joule of a particle of mass 1 kg moving in x-y plane obeys the law U = 3x + 4y , where (x,y) are the co-ordinates of the particle in metre. If the particle is at rest at (6,4) at time t = 0 then :

The potential energy phi in joule of a particle of mass 1 kg moving in x-y plane obeys the law, phi=3x + 4y . Here, x and y are in metres. If the particle is at rest at (6m, 8m) at time 0, then the work done by conservative force on the particle from the initial position to the instant when it crosses the x-axis is . a) 25 J b) 25 J c) 50 J d) - 50 J

The potential energy phi in joule of a particle of mass 1 kg moving in x-y plane obeys the law, phi=3x + 4y . Here, x and y are in metres. If the particle is at rest at (6m, 8m) at time 0, then the work done by conservative force on the particle from the initial position to the instant when it crosses the x-axis is .

The potential energy U (in J ) of a particle is given by (ax + by) , where a and b are constants. The mass of the particle is 1 kg and x and y are the coordinates of the particle in metre. The particle is at rest at (4a, 2b) at time t = 0 . Find the coordinates of the particle at t =1 second.

The potential energy U (in J ) of a particle is given by (ax + by) , where a and b are constants. The mass of the particle is 1 kg and x and y are the coordinates of the particle in metre. The particle is at rest at (4a, 2b) at time t = 0 . Find the speed of the particle when it crosses y-axis.