If `A=[0 1 2 1 2 3 3x1]a n dA^(-1)=[1/2-1/2 1/2-4 3y5/2-3/2 1/2]` `x=1,y=-1` (b) `x=-1,y=1` `x=2,y=-1/2` (d) `x=1/2,y=1/2`

If A=[[0,1,3],[1,2,x],[2,3,1]] and A^(-1)=[[(1)/(2),-4,(5)/(2)],[-(1)/(2),3,-(3)/(2)],[(1)/(2),y,(1)/(2)]] . Find x,y

The intercept on the line y=x by the circle x^2+y^2-2x=0 is AB. Equation of the circle with AB as a diameter is (A) (x-1/2)^3+(y-1/2)^2=1/2 (B) (x-1/2)^2+(y-1/2)^2=1/4 (C) (x+1/2)^2+(y+1/2)^2=1/2 (D) (x+1/2)^2+(y+1/2)^2=1/4

If |[ x y 1 1 ]|=2 and |[ x 3 y 2 ]|=1 then

(x + 2) (x + 1) = (x -2) (x -3) (y+3)(y+2)=(y-1)(y-2)

(5) / (x-1) + (1) / (y-2) = 2 (6) / (x-1) - (3) / (y-2) = 1

If x+2y=[[2,0,3],[1,-1,1]] and 2x-y=[[1,-4,-5],[0,2,-1]] then

If x+2y=[[2,0,3],[1,-1,1]] and 2x-y=[[1,-4,-5],[0,2,-1]] ,then

The equation of the straight line passing through the point (4,3) and making intercepts on the co-ordinate axes whose sum is -1 is (a) (x)/(2)-(y)/(3)=1 and (x)/(-2)+(y)/(1)=1(x)/(2)-(y)/(3)=-1 and (x)/(-2)+(y)/(1)=-1 (c) (x)/(2)+(y)/(3)=1 and (x)/(2)+(y)/(1)=-1(x)/(2)+(y)/(1)=-1 and (x)/(-2)+(y)/(1)=-1

The equation of the plane thorugh the point (-1,2,0) and parallel to the lines x/3=(y+1)/0=(z-2)/(-1) and (x-1)/1=(2y+1)/2=(z+1)/(-1) is (A) 2x+3y+6z-4=0 (B) x-2y+3z+5=0 (C) x+y-3z+1=0 (D) x+y+3z-1=0