If `(x_1, y_1)&(x_2, y_2)` are the ends of diameter of a circle such that `x_1&x_2` are the roots of the equation `a x^2+b x+c=0` and `y_1&y_2` are the roots of the equation `p y^2+q y+c=0` . Then the coordinates f the centre of the circle is: `(b/(2a), q/(2p))` (b) `(-b/(2a),=q/(2p))` `(b/a , q/p)` (d) None of these

If (x_(1),y_(1))&(x_(2),y_(2)) are the ends of a diameter of a circle such that x_(1)&x_(2) are the roots of the equation ax^(2)+bx+c=0 and y_(1)&y_(2) are the roots of the equation py^(2)=qy+c=0. Then the coordinates of the centre of the circle is: ((b)/(2a),(q)/(2p))(-(b)/(2a),(q)/(2p))((b)/(a),(q)/(p)) d.none of these

The abscisae of A and B are the roots of the equation x ^(2) + 2ax -b ^(2) =0 and their ordinates are the roots of the equation y ^(2) + 2 py -q ^(2) =0. The equation of the circle with AB as diameter is

A abscissa of A and B are the roots of the equation x^2+2ax-b^2=0 and their ordinates are roots of the equation y^2+2py-q^2=0 . The equation of the circle with AB as diameter is

The equation of the circle whose one diameter is PQ, where the ordinates of P, Q are the roots of the equation x^(2)+2x-3=0 and the abscissae are the roots of the equation y^(2)+4y-12=0 is

Abscissas of two points P and Q are roots of the equation x^(2) + 2x - 3 =0 while their ordinates are roots of y^(2) + 4y - 12 = 0 . The centre of the circle with PQ as a diameter is

The abscissa of two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of y^(2)+2py-q^(2)=0 then the distance AB in terms of a,b,p,q is

If the abscissa and ordinates of two points P and Q are the roots of the equations x^(2)+2ax-b^(2)=0 and x^(2)+2px-q^(2)=0 respectively,then find the equation of the circle with PQ as diameter.

If the roots of the equation (x_(1)^(2)-a^(2))m^(2)-2x_(1)y_(1)m+y1^(2)+b^(2)=0 are the slopes of two perpendicular lines intersecting at P, then locus of P is