If `tantheta=t t h e nt a n2theta+sec2theta` is equal to `(1+t)/(1-t)` (b) `(1-t)/(1+t)` (c) `(2t)/(1-t)` (d) `(2t)/(1+t)`

If tantheta= t, then tan2theta+sec2theta is equal to (a) (1+t)/(1-t) (b) (1-t)/(1+t) (c) (2t)/(1-t) (d) (2t)/(1+t)

If tan theta=thentan2theta+sec2 theta is equal to (1+t)/(1-t)(b)(1-t)/(1+t)(c)(2t)/(1-t)(d)(2t)/(1+t)

If tan theta =t, then tan 2 theta + sec 2 theta = ............... A) (1+t)/(1-t) B) (1-t)/(1+t) C) (2t)/(a-t) D) (2t)/(1+t)

If tantheta=(2t)/(1-t^(2)) then sin theta+cos theta equals

If tan ( theta/2)=t then ( 1-t^2 )/( 1+t^2) is equal to

If tan(theta/2)=t then (1-t^2)/(1+t^2) is equal to

If tan ""(theta)/(2) = t, then the value of (1- t ^(2))/(1+t^(2)) is

If tan ""(theta)/(2) = t, then the value of (1- t ^(2))/(1+t^(2)) is

If x = sin t and y = tan t , then (dy)/(dx) is equal to a) cos ^(2) t b) (1)/( cos ^(3) t ) c) (1)/( cos ^(2) t ) d) sin ^(2) t