`intxlogsinx dx`

If u and v are two functions of x then prove that : int uv dx = u int v dx - int [ (du)/(dx) int v dx ] dx Hence, evaluate int x e^(x) dx

int(dx)/(1+sin6x)dx=

If y=log(1+sinx)," then "(d^(3)y)/(dx^(3))+(d^(2)y)/(dx^(2))(dy)/(dx)=

int d/dx(f(x)) dx=d/dx int f(x)dx (True/false)

Find int(dx)/(dx+b)