If |bar(a)|=|bar(b)|=|bar(c)|=2, and bar...

If `|bar(a)|=|bar(b)|=|bar(c)|=2`, and `bar(a)bar(b)=bar(b).bar(c)=bar(c)bar(a)=2` then `[bar(a) bar(b) bar(c)]`=
(1).`3sqrt(2)` (2).`4sqrt(2)` (3).32 (4).48

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