If the AD,BE,CF are the lengths of the medians of a `DeltaABC` then general solution of the equation `cos theta=sqrt((AD^(2)+BE^(2)+CF^(2))/(AB^(2)+BC^(2)+CA^(2)))` is (where z is the set of all integers)

[ "If the "AD,BE" ,"CF" are the lengths of the medians of a "/_\ABC" then general solution of the equation "],[cos theta=sqrt((AD^(2)+BE^(2)+CF^(2))/(AB^(2)+BC^(2)+CA^(2)))" is "],[" (where "z" is the set of all integers) "]

Find the general solutions of the following equation: cos ec theta=-sqrt(2)

Find the general solution of the trigonometric equation :cos theta=-(sqrt(3))/(2)

The general solution of 2cos2 theta-sqrt(3)=0 is

The general solution of 2cos2theta-sqrt3=0

Find the general solution of the given following equations sin theta=-(sqrt(3))/(2)cos ec theta=-2

If AD, BE and CF are the medians of a ABC ,then (AD^(2)+BE^(2)+CF^(2)):(BC^(2)+CA^(2)+AB^(2)) is equal to

If AD, BE and CF are the medians of a Delta ABC, then evaluate (AD^(2)+BE^(2)+CF^(2)): (BC^(2) +CA^(2) +AB^(2)).