Calculate hybride orbitals (X) and pure orbitals (Y) in `CH_(2)=CH-CH=CH_(2)` .Find the value of X/Y

Calculate the ratio between hybrid orbitals and pure orbitals in Allene. CH_2 = C = CH_2

The ratio of pure and hybrid orbitals H_(2)C=CH-CH=CH_(2)

Which hybrid orbitals are involved in the CH_(3)-CH=CH-CH_(3) compound

CH_(3)-CH=CH_(2)+HI rarr X . Here X is

What hybrid orbitals will form the following compound H_(3)C-CH=CH-CH_(2)-CH_(3)

CH_(2)=CH-CH_(2)-Cl overset(HOC l)to (X) is

The hybrid orbitals that will form the compound CH_3 - C -= C - CH_2 - CH_3 are:

The following reaction is a x,y-addition reaction. H_(2)C=CH-CH=CH_(2)+HBr to H_(3)C-CH=CH-CH_(2)Br The value of (x+y) is:

The total number of hybrid orbitals involved in the formation of following compound is/are CH_(2)=C=CH_(2)