`bar(a),bar(b),bar(c)` are vectors such that `[bar(a)bar(b)bar(c)]=4` then
`[bar(a)timesbar(b) bar(b)timesbar(c) bar(c)timesbar(a)]` is
(A) 16 (B) 64 (C) 4 (D)8

If bar(a)+bar(b)+bar(c)=bar(0) then bar(a)timesbar(b)=

If [bar(a) bar(b) bar(c)]=2 then [2(bar(b)timesbar(c))(bar(-c)timesbar(a))(bar(b)timesbar(a))] is equal to

If [bar(a) bar(b) bar(c)]=2 ,then [2(bar(b)timesbar(c))(-bar(c)timesbar(a))(bar(b)timesbar(a))] is equal to

If bar(a)+2bar(b)+3bar(c)=bar(0) then bar(a)xxbar(b)+bar(b)xxbar(c)+bar(c)xxbar(a)=

Let bar(a),bar(b),bar(c) be three non-zero vectors such that bar(a)+bar(b)+bar(c)=0 .Then lambda(bar(a)timesbar(b))+bar(c)timesbar(b)+bar(a)timesbar(c)=0 where lambda is

if bar(a),bar(b),bar(c) are any three vectors then prove that [bar(a),bar(b)+bar(c),bar(a)+bar(b)+bar(c)]=0

If |bar(a)| =2 and |bar(b)|=3 and bar(a) .bar(b)=0 then |(bar(a)times(bar(a)times(bar(a)times(bar(a)timesbar(b)))))| (A) 16 (B) 32 (C) 48 (D) 0

If bar(a),bar(b),bar(c) are three non zero vectors,then bar(a).bar(b)=bar(a).bar(c)rArr

If a and b are unit vectors such that |bar(a)timesbar(b)|=bar(a)*bar(b) then |bar(a)-bar(b)|^(2)=

bar(a),bar(b),bar(c) are three unit vectors such that bar(a)xx(bar(b)xxbar(c))(1)/(2)bar(b), then (bar(a),bar(b))=(bar(a),bar(c))=(bar(b),bar(c)), are non-collinear)