The area of cross-section of the wider tube shown in fig., is `800cm^(2)` . If a mass of 12 kg is placed on the massless piston, what is the difference in the level of water in two tubes.

The area of cross section of the wider tube shown in figure is 900 cm^2 . If the boy standing on the piston weights 45 kg, find the difference in the levels of water in the two tubes.

In the figure, the cross-sectional area of the smaller tube is a and that of the larger tube is 2a . A block of mass m is kept in the smaller tube having the base area that of the tube. The difference between water levels of the two tubes is

Fig, shows a U-tube of uniform cross-sectional area A accelerated with acceleration a as shown. If d is the seperation between the limbs. Then the difference in the levels of the liquid in the U-tube is

The two arms of a Verical U tube have internal radii of 0.4 cm and 0.8 cm respectively . The tube contains water . What is the difference in the surface levels of water in the two arms ? S.T of water = 70 xx10^(-3) N/m

A liquid of density 800 kg//m^3 flowing steadily in a tube of varying cross-section. If area of cross-section at A is 4 cm^2 and at B is 2 cm^2 . If speed of liquid at A is 10 cm//s , calculate (i) the rate of flow (ii) the difference in pressures at A and B .

STATEMENT-1 : Time period of the liquid executing S.H.M.in a U-tube depends on the area of cross section of U-tube. and STATEMENT-2 : The restoring force acting on liquid displaced from equilibrium position of U -tube depends on the difference in levels of liquid in the two limbs of U -tube.

Figure shows a liquid being pushed out of a tube by pressing a piston. The area of cross section of the piston is 1.0 cm^2 and that of the tube at the outlet is 20 mm^2 . If the piston is pushed at a speed of 2cms^-1 . What is the speed of the outgoing liquid?