The vertex A of `DeltaABC` is (3,-1). The equation of median BE and angle bisector CF are x-4y+10=0 and 6x+10y-59=0, respectively. Equation of AC is

The vertex A of triangle ABC is at origin.The equation of median through B and C are 15x-4y=240 and 15x-52y+240=0 respectively.Then

The vertex C of a triangle ABC is (4,-1) . The equation of altitude AD and Median AE are 2x-3y+12=0 and 2x+3y=0 respectively then slope of side AB is :

Find equation of angle bisector of plane x+2y+3z-z=0 and 2x-3y+z+4=0 .

In Delta ABC equation of the right bisectors of the sides Ab and AC are x+y = 0 and x - y = 0 respectively .If A = (5,7) then equation of side BC is

Equation of angle bisector of the lines 3x-4y+1=0 and 12x+5y-3=0 containing the point (1,2)

Let A, B and C be the vertices of a triangle, equation of perpendicular bisectors of AB and AC are x-y +3 =0 and x+2y + 12=0 respectively If co-ordinates of A are (2,3), then equation of BC is

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is

The equations of perpendicular bisectors of the sides AB and AC of a DeltaABC are x - y + 5 = 0 and x+2y = 0 , respectively. If the point A is (1, - 2) the equation of the line BC is

Find the equation of the sides of a triangle ABC with A(1,3) as a vertex and x-2y+1=0 and y-1=0 as the equation of two of its medians.