f(x)=|x[x]| in `-1<=x<=2` where [x] is greatest integer `<=x` then f(x) is

A function f defined as f(x)=x[x] for -1lexle3 where [x] defines the greatest integer lex is

f(x) = |x| + |x-1| at x = 1 .

f(x) = |x| + |x-1| at x = 1 .

Where 0<=x<=1,f(x)=|x|+|x-1| is

Discuss the continuity of the f(x) at the indicated points: f(x)=|x|||x-1| at x=0,1f(x)=|x-1|+|x+1| at x=-1,1

Verify Rolle's theorem for f(x)=x,x in[1,2] .

If f(x)=-x|x| , then f^(-1)(x) is :

If f(x)=-x|x| ,then f^(-1)(x) is :

Let F(x) = x|x| , x = 1 then

If f(x)= | x|+|x-1| , then in [-1, 2]