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If E(1), E(2), E(3) are independent even...

If `E_(1), E_(2), E_(3)` are independent events, such that `P(E_(1)nnbar(E_(2))nnbar(E_(3)))=1/4, P(bar(E_(1))nnbar(E_(2))nnbar(E_(3)))=1/8, P(bar(E_(1))nnE_(2)nnbar(E_(3)))=1/8`. Find `P(bar(E_(3)))`

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