If `a="max"{(x+2)^(2)+(y-3)^(2)} and b="min"{(x+2)^(2)+(y-3)^(2)}` where x, y satisfying `x^(2)+y^(2)+8x-10y-40=0` then :

Let x and y be real variables satisfying x^(2)+y^(2)+8x-10y-40=0. Let a=max{sqrt((x+2)^(2)+(y-3)^(2))} and b=min{sqrt((x+2)^(2)+(y-3)^(2))}. Then a+b=18( b) a+b=sqrt(2)a-b=4sqrt(2)( d) a*b=73

Find the real points (x,y) satisfying 3x^(2)-3y^(2)-4xy+10x-10y+10=0

Let x, y be real variable satisfying x^(2) + y^(2) + 8x - 10y - 59 = 0 Let a = max {(x-3)^(2) + (y-4)^(2) and b = min {(x-3)^(2) + (y-4)^(2)) , then a + b + 2010 is ______ .

Two circles x^(2) + y^(2) - 4x + 10y + 20 = 0 and x^(2) + y^(2) + 8x - 6y - 24= 0

(x + 2) (x + 1) = (x -2) (x -3) (y+3)(y+2)=(y-1)(y-2)

I. 6x^(2)+x-1=0 II. 8y^(2)+10y+3=0

The number of solutions (x,y) where x and y are integers,satisfying 2x^(2)+3y^(2)+2x+3y=10 is

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))