2.5 ml of a gaseous hydrocarbon exactly requires 12.5 ml oxygen for complete combustion and produces 7.5 ml carbon dioxide and 10.0 ml water vapour. All the volumes are measured at the same pressure and temperature. Show that the data illustrates Gay Lussac’s law of volume combination.

20 ml of a hydro carbon requires 100 ml of oxygen for complete combustion. In this reaction 60 ml of carbondioxide is produced. The formula of hydro carbon is

10 mL of a certain hydrocarbon require 25 mL of oxygen for complete combustion and the volume CO_(2) of product is 20 mL. What is the formula of hydrocarbon ?

10 mL of a certain hydrocarbon require 25 mL of oxygen for complete combustion and the volume CO_(2) of product is 20 mL. What is the formula of hydrocarbon ?

15mL of a gaseous hydrocarbon required for complete combustion, 357mL air contianing 21% oxygen by volume. The gaseous product occupied 327mL. If all the volumes are measured at STP. The molecular formula of hydrocarbon will be:

36 ml of a gaseous mixture consisting of a gaseous organic compound A and just sufficient amount of oxygen required for complete combustion gives 16 ml of CO_(2) , 24 ml water vapour and 8 ml of N_(2) . The volumes are measured at same temperature and pressure. Volume of O_(2) required for complete combustion

36 ml of a gaseous mixture consisting of a gaseous organic compound A and just sufficient amount of oxygen required for complete combustion gives 16 ml of CO_(2) , 24 ml water vapour and 8 ml of N_(2) . The volumes are measured at same temperature and pressure. Volume of O_(2) required for complete combustion