`1/(4piepsilon_(0))=9xx10^(9)` न्यूटन`xx` मीट`र^(2)`/कूलॉ`म^(2)`

An electric dipole is prepared by taking two electric charges of 2 xx 10^(-8) C separated by distance 2 mm. This dipole is kept near a line charge distribution having density 4 xx 10^(-4) C/m in such a way that the negative electric charge of the dipole is at a distance 2 cm from the wire as shown in the figure. Calculate the force acting on the dipole. [Take k=1/(4piepsilon_(0)) = 9 xx 10^(9) Nm^(2)C^(-2) ]

The value of electric field at a region of space is given by, E=Ar where A=100V .m^(2) and r=distance (in m) from origin inside the electric field. Find the amount of charge enclosed in a sphere of radius 20 cm centered at the origion. Given 1/(4piepsilon_(0))=9xx101/(4piepsilon_(0))=9xx10^(9)N.m^(2).c^(-2)

A total charge of 5 muC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9xx10^(8) NC^(-1) , then the radius of the cup is (1/(4pi epsi_(0))=9xx10^(9) N-m^(2) C^(-2))

(-2)xx(-4)xx(-9)

What is the magnitude of a point charge due to which the electric field 30 cm away has the magnitude 2 newton / coulomb ? [1/(4piepsilon_0)=9xx10^9 (Nm^2)/C^2]

'alpha particle' of 3.6 MeV are fired toward nucleus ._(Z)^(A)X, at point of closest separation distance between 'alpha particle' and 'X' is 1.6xx10^(-14)m. Calculate atomic number of 'X'. ["Given":1/(4piepsilon_(0))=9xx10^(9) "in S.I.units"]

Shown in the figure four point charges at the corners of a square of side 2 cm. Find the magnitude and direction of the electric field at the centre O of the square, if Q = 0.02 muC Use 1/(4piepsilon_0) = 9 xx 10^9 N m^2 C^-2