Home
Class 12
MATHS
One of extremity of minor of ellipse is ...

One of extremity of minor of ellipse is `B`. `S` and `S\'` are focii of ellipse then area of right angle `/_\SBS\'` is equal to 8. Then latus rectum of ellipse is equal to (A) `4` (B) `4/sqrt2` (C) `2sqrt2` (D) `3/sqrt2`

Promotional Banner

Similar Questions

Explore conceptually related problems

One of extremity of minor of ellipse is B.S and S backslash 'are focii of ellipse then area of right angle /_SBS backslash is equal to 8. Then latus rectum of ellipse is equal to (A) 4(B)(4)/(sqrt(2))(C)2sqrt(2)(D)(3)/(sqrt(2))

Find the eccentricity of the ellipse if the length of rectum is equal to half the minor axis of the ellipse .

B is extermity of the minor axis of an elipse whose foci are S and S'. If angle SBS' is a right angle, then the eccfentricity of the ellipse is

B is extermity of the minor axis of an elipse whose foci are S and S'. If angle SBS' is a right angle, then the eccfentricity of the ellipse is

If the latus rectum of an ellipse is equal to half of minor axis, then its eccentricity is

Length of latus rectum of the ellipse 2x^2 + y^2 - 8x+2y+7=0 is (A) 8 (B) 4 (C) 2 (D) sqrt(2)

Length of latus rectum of the ellipse 2x^2 + y^2 - 8x+2y+7=0 is (A) 8 (B) 4 (C) 2 (D) sqrt(2)

The length of latus rectum of the ellipse 3x^(2) + y^(2) = 12 is (i) 4 (ii) 3 (iii) 8 (iv) (4)/(sqrt(3))

If the eccentricity of an ellipse be (1)/(sqrt2), then its latus rectum is equal to its