If `x=sin^3t/(sqrtcos2t), y=cos^3t/sqrt(cos2t)` show that `dy/dx =0 at t=pi/6`

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x= sin^3t/sqrt x cos2t , y= cos^3t/ sqrt x cos2t .

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Find dy/dx if x = (sin^3t)/(sqrtcos2t), y = (cos^3t)/(sqrtcos2t)

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