`Xe+O_(2)F_(2) overset(155 K) to`

Complete the following reactions : (i) NH_(4)Cl(aq) overset("heat") to (ii) P_(4)+NaOH+H_(2)O to (iii) Xe (g) +F_( 2)(g) overset(673 K)underset(1 " bar")to " " (iv) Sn +PCl_(5) overset("heat") to (v) HgCl_(2)+PH_(3) to

Complete the following reaction : XeF_4+ O_2F_2 overset (143K) rarr

A posible mechanism for the reaction : 2NO + 2H_(2) to N _(2) + 2H_(2) O is : (i) 2NO + overset(k _(1))hArr N _(2) O _(2) (ii) N _(2) O _(2) + H _(2) overset(k _(2))to N _(2) O + H _(2) O (iii) N _(2)O + H _(2) overset(k _(3)) to N _(2) + H _(2)O If the second step is the rate determining step then rate law may be written as : ?

underset((2 : 1 "ratio"))(Xe + F_(2)) overset(Ni//675 K)rarr Z The compound Z in the above reaction is

XeF_(6)+H_(2)O overset(excess)to Product. How many hybrid orbitals will be present in Xe in product?

XeF_(6)+H_(2)O overset(excess)to Product. How many hybrid orbitals will be present in Xe in product?

underset((1:20))(Xe+F_(2)) overset(573K,60-70" bar")to? The compound formed in above reaction is

K_(2)Cr_(2)O_(7) overset(Delta) to K_(2)CrO_(4)+Cr_(2)O_(3)+O_(2)uarr

K_(2)Cr_(2)O_(7) overset(Delta) to K_(2)CrO_(4)+Cr_(2)O_(3)+O_(2)uarr