" The function "f:[0,oo)rarr R" given by "f(x)=(x)/(x+1)" is: "

The function f:[0,oo] to R given by f(x)=(x)/(x+1) is

Prove that the function f: [0,oo)rarr R , given by f(x) =9x^(2) +6x -5 is not invertible. Modify the codomain of the functions to make it invertible, and hence find f^(-1)

Show that the function f:R-{3}rarr R-{1} given by f(x)=(x-2)/(x-3) is a bijection.

Show that the function f:R-{3}rarr R-{1} given by f(x)=(x-2)/(x-3) is bijection.

The function f : (0, oo) rarr [0, oo), f(x) = (x)/(1+x) is

The function f : (0, oo) rarr [0, oo), f(x) = (x)/(1+x) is

A function f:(0,oo)rarr[0,oo] is given by f(x)=|1-(1)/(x)|, then f(x) is (A) Injective but not surjective (B) Injective and bijective (C) Injective only (D) Surjective only

Show that the logarithmic function f:R_(0)^(+)rarr R given by f(x)=log_(a)x,a>0 is bijection.

If the function f:[1, oo) rarr [ 1,oo) defined by f(x) = 2^(x(x -1)) is invertible, then find f^(-1) (x).

The domain of the function f :R rarr R defined by f(x)=sqrt(x^(2)-3x+2) is (-oo,a]uu[b,oo) then a+ b=