" If "cos theta=(a cos phi+b)/(a+b cos phi)" then "ln theta/2" is equal to "

If cos theta=(a cos phi+b)/(a+b cos phi) then tan^(2)((theta)/(2)) is equal to

If cos theta = (a cos phi + b) / (a + b cos phi) then (tan ((theta) / (2))) / (tan ((phi) / (2))) = (A) ( ab) / (a + b) (B) (a + b) / (ab) (C) sqrt ((a + b) / (ab)) (D) sqrt ((ab) / (a + b))

If cos theta =(a cos phi+b)/(a+bcosphi) then ("tan"(theta)/2)/("tan"(phi)/2)=

If cos(theta+phi)=m cos(theta-phi) then tan theta is equal to

cos 2theta cos 2phi + sin^(2) (theta - phi ) - sin^(2) ( theta + phi) is equal to