For a semiconductor of band energy gap `1.5eV`, calculate the wave-length of the emitted radiation when a conduction hand electron combines with a valence band hole. Given Planck's constat `6.6xx10^(-34)Js`

Forbidden energy gap of Ge is 0.75eV , maximum wave length of incident radiation for producing electron-hole pair in germanium semiconductor is

Energy band gap of gallium arsenide phosphate is 1.98 eV.Calculate the wavelength of electromagnetic radiation emitted,when electrons and holes combine in this alloy semiconductor directly.

Calculate the wavelength of a photon of energy 10^(10) eV (electron volt(. Given Planck.s constant h=6.625 xx 10^(-34) Js (Joule Second).

when a certain energy is applied to an hydrogen atom, an electron jumps from n =1 to n = 3 state. Find (i) the energy absorbed by the electron. (ii) wavelength of radiation emitted when the electron jump back to its initial state. ( Energy of electron in first orbit = - 13.6 eV , Planck's constant = 6.6225 xx10^(-34) Js, Charge on electron = 1.6 xx10^(-19) C, speed of light in vacuum = 3xx10^(8)ms^(-1)

When light of frequency 6 xx 10^(14) Hz is incident on a photosensitive metal, the kinetic energy of the photoelectron ejected is 2e V. Calculate the kinetic energy of the photoelectron in eV when light to frequency 5 xx 10^(14) Hz is incident on the same metal. Given Planck's constant, h = 6.625 xx 10^(-34) Js , 1 eV = 1.6 xx 10^(-19) .

The bank gap of an alloy semiconductor galiumarseide phosphie is 1.98eV . Calculate the wavelength of radiation that is emitted when electrons and holes in this material combine directly. What is the colour of the emitted radiation? Take h=6.6xx10^(-34) Js

The forbidden energy gap of a germanium semiconductor is 0.75 eV. The minimum thermal energy of electrons reaching the conduction band from the valence band should be -