सिद्ध कीजिए कि : `bar(i)cdot(bar(j)xxbar(k))+(bar(i)xxbar(k))cdot bar(j)=0`.

Compute [bar(i) - bar(j). bar(j) - bar(k). bar(k) -bar(i)] .

If bar(a)xxbar(b)=bar(c) and bar(b)xxbar(c)=bar(a), then

Compute 2 bar(j) xx (3bar(i) - 4bar(k)) + (bar(i)+2bar(j)) xx bar(k) .

If bar(a)=bar(i)-2bar(j)+bar(k), bar(b)=2bar(i)+bar(j)+bar(k), bar(c ) = bar(i) + 2bar(j)-bar(k) , then find bar(a) xx (bar(b) xx bar(c )) and |(bar(a)xxbar(b))xxbar(c )| .

If bar(a)=bar(i)+bar(j)-2bar(k) then sum[(bar(a)xxbar(i))xxvec j]^(2)=

If bar(a)=bar(i)+bar(j)-bar(2)k then sum[(bar(a)xxbar(i))xxvec j]^(2)=

If bar(a)xxbar(b)=bar(c)xxbar(d),bar(a)xxbar(c)=bar(b)xxbar(d) then

(bar(a)xxbar(i))(bar(b)xxbar(i))+(bar(a)xxbar(j))(bar(b)xxbar(j))+(bar(a)xxbar(k))(bar(b)xxbar(k))=

bar (a) = bar (a) + bar (j) + bar (k), bar (b) = bar (i) + bar (j), bar (c) = bar (i) and (bar (a) xxbar (b)) xxbar (c) = lambdabar (a) + mubar (b), then lambda + mu =

Let bar(a)=bar(i)+bar(j), bar(b)=bar(j)+bar(k) and bar(c)=alphabar(a)+betabar(b) . If the vectors bar(i)-2bar(j)+bar(k), 3bar(i)+2bar(j)-bar(k) and bar(c) are coplanar then alpha/beta equals