हल कीजिए :
`2(x+1)-3(y-1)=13`
`7(x+1)-2(y-1)=20`.

2x-3y=13; 7x-2y=20

निम्न समीकरण को हल कीजिए - tan^(-1)(x-1)+tan^(-1)(x)+tan^(-1)(x+1)=tan^(-1) 3 x

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

Solve the following simultaneous equations: 7/(2x+1)+13/(y+2)=27,13/(2x+1)+7/(y+2)=33

Find x, y if [(-2,0),(3,1)][(-1),(2x)]+[(-2),(1)]=2[(y),(3)]

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

If (x , y) is a variable point on the line y=2x lying between the lines 2(x+1)+y=0 and x+3(y-1)=0 , then x in (-1/2,6/7) (b) x in (-1/2,3/7) y in (-1,3/7) (d) y in (-1,6/7)