The current in a discharging LR circuit without the battery drops from 2.0 A to 0.10 s. (a) find the time constant of the circuit. (b) if the inductance of the circuit is 4.0 H, what is its resistance?

The current in a discharging LR circuit without the battery drops from 2.0 A to 1.0A in 0.10 s. (a) find the time constant of the circuit. (b) if the inductance of the circuit is 4.0 H, what is its resistance?

The current in a discharging LR circuit without the battery drops from 2.0 A to 1.0A in 0.10 s. (a) find the time constant of the circuit. (b) if the inductance of the circuit is 4.0 H, what is its resistance?

The current in a discharging LR circuit is given by I = i_0 e^(-t/tau) where tau is the time constant of the circuit. Calculate the rms current for the period t = 0 to t = tau .

The current in a discharging LR circuit is given by I = i_0 e^(-t/tau) where tau is the time constant of the circuit. Calculate the rms current for the period t = 0 to t = tau .

The current in a discharging LR circuit is given by I = i_0 (t/tau) where tau is the time constant of the circuit. Calculate the rms current for the period t = 0 to t = tau .

The current in a discharging LR circuit is given by I = i_0 (t/tau) where tau is the time constant of the circuit. Calculate the rms current for the period t = 0 to t = tau .

In an LR circuit, current at t = 0 is 20 A . After 2 s it reduces to 18 A . The time constant of the circuit is :