[" If two concentric ellipse be such that the foci of one be on the other and if "3/5" and "4/5" be their eccentricities.If "theta" be "],[" the angle between their axes,then the value of "1+sin theta+sin^(4)theta" must be "]

Two concentric ellipse be such that the foci of one be on the other and if 3/5 and 4/5 be their eccentricities. If theta is the angle between their axes, then the values of 2(1+sin^(2)theta+sin^(4)theta) must be

Two concentric ellipse be such that the foci of one be on the other and if 3/5 and 4/5 be their eccentricities. If theta is the angle between their axes, then the values of 2(1+sin^(2)theta+sin^(4)theta) must be

If sin5theta=cos4theta then the value of theta is

If 3 sin theta + 4 cos theta =5 , then value of sin theta is

If (sin theta + cos theta)/(sin theta - cos theta)=3 , then the value of sin^(4)theta - cos^(4)theta is:

If sin theta=(4)/(5) , find the value of sin2theta :

Two concentric ellipses are such that the foci of one are on the other and their major axes are equal. Let ea n de ' be their eccentricities. Then. the quadrilateral formed by joining the foci of the two ellipses is a parallelogram the angle theta between their axes is given by theta=cos^(-1)sqrt(1/(e^2)+1/(e^('2))=1/(e^2e^('2))) If e^2+e^('2)=1, then the angle between the axes of the two ellipses is 90^0 none of these

Two concentric ellipses are such that the foci of one are on the other and their major axes are equal. Let ea n de ' be their eccentricities. Then. the quadrilateral formed by joining the foci of the two ellipses is a parallelogram the angle theta between their axes is given by theta=cos^(-1)sqrt(1/(e^2)+1/(e^('2))=1/(e^2e^('2))) If e^2+e^('2)=1, then the angle between the axes of the two ellipses is 90^0 none of these

Two concentric ellipses are such that the foci of one are on the other and their major axes are equal. Let ea n de ' be their eccentricities. Then. the quadrilateral formed by joining the foci of the two ellipses is a parallelogram the angle theta between their axes is given by theta=cos^(-1)sqrt(1/(e^2)+1/(e^('2))=1/(e^2e^('2))) If e^2+e^('2)=1, then the angle between the axes of the two ellipses is 90^0 none of these