In the shown AC circuit phase different between current `I_(1)` and `I_(2)` is

In the given circuit assuming inductor and source to be ideal, the phase differece between current I_(1) and I_(2) :

In the circuit shown in figure : R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega and C = (sqrt(3))/(2) mF . Current in L - R_(1) circuit is I_(1) in C - R_(1) circuit is I_(2) and the main current is I Phase difference between I_(1) and I_(2) is

In the circuit shown in figure : R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega and C = (sqrt(3))/(2) mF . Current in L - R_(1) circuit is I_(1) in C - R_(1) circuit is I_(2) and the main current is I Phase difference between I_(1) and I_(2) is

In the circuit shown in figure : R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega and C = (sqrt(3))/(2) mF . Current in L - R_(1) circuit is I_(1) in C - R_(1) circuit is I_(2) and the main current is I Phase difference between I_(1) and I_(2) is

In an a.c. circuit , phase difference between current and potential is pi//4 . The variation of I and E versus t is represented in the graph. If E = E_0 cos (100 t) , then the component of the circuit are

In an AC circuit X_(C)=X_(L) . The phase differe3nce between the current and voltage will be

In the circuit shown in Fig. (i) find the phase difference between the currents through L and R_(1) (ii) find the phase difference between potential differece across C and R_(2)