[15dn/_ABC,D" is the midpoint of "BC" and "AE perp BC" .If "AC>AB" ,show that "],[AB^(2)=AD^(2)-BC*DE+(1)/(4)BC^(2)" ."]

In Delta ABC , D is the midpoint of BC and AE bot BC . If AC gtAB , show that AB^(2)=AD^(2)-BC*DE+(1)/(4)BC^(2)

In a triangle ABC,AC>AB,D is the mid- point of BC and AE perp BC .Prove that: (i) AC^(2)=AD^(2)+BCDE+(1)/(4)BC^(2)

In a triangle ABC,AC>AB,D is the mid- point of BC and AE perp BC .Prove that: (i) AB^(2)=AD^(2)-BCDE+(1)/(4)BC^(2)( (ii) AB^(2)+AC^(2)=2AD^(2)+(1)/(2)BC^(2)

In a triangle ABC, D is midpoint of side BC. If ACgtAB and AE_|_BC , then prove that AB^(2)=AD^(2)-BC.ED+(1)/(4)BC^(2)

Seg AD is the median of /_ABC and AM perp BC. Prove that :(i)AC^(2)=AD^(2)+BC xx DM+((BC)/(2))^(2)(ii)AB^(2)=AD^(2)-BC xx DM+((BC)/(2))^(2)

The given figure shows a triangle ABC, in which AB gt AC. E is the mid-point of BC and AD is perpendicular to BC. Prove that : AB^(2) +AC^(2) =2BE^2 +2AE^2

In figure, AD is a median of a triangle ABC and AM bot BC. Prove that AC ^(2) + AB ^(2) = 2 AD ^(2) + (1)/(2) BC ^(2).

In Delta ABC seg AD perp seg BC,DB=3CD Prove that 2AB^(2)=2AC^(2)+BC^(2)

In figure,/_B<90^(@) and AD perp BC .Prove that AC^(2)=AB^(2)+BC^(2)-2BC.BD

In triangle ABC, AB > AC. E is the mid-point of BC and AD is perpendicular to BC. Prove that : AB^2 +AC^2=2AE^2 +2BE^2