` cos(40^(@) - theta ) - sin (50^(@) + theta )+ ( cos^(2) 40^(@) + cos^(2) 50^(@))/( sin^(2) 40^(@) + sin^(2) 50^(@))` व्यंजक के मान ज्ञात करो ।

cos (40^@ + theta) - sin (50^@ - theta) is equal to

Solve cos(50^(@)+ theta) = sin (30^(@)+theta) .

Value of [cos(40^@ + theta) - sin (50^@ - theta)] is

Evaluate: sin^(2)40^(@)-cos^(2)50^(@)

What is the value of 4(cos^(2)(10^(@))+cos^(2)(50^(@))-sin40^(@)sin80^(@))

sin^(2)50^@+cos^(2)50^@=?

sin(50^(@)+theta)-cos(40^(@)-theta)

cos 40^(@)=0.76 then sin 50^(@) =………….

Without using trigonometric tables,evaluate each of the following: (sin^(2)20^(@)+sin^(2)70^(@))/(cos^(2)20^(0)+cos^(2)70^(@))+(sin(90^(@)-theta)sin theta)/(tan theta)+(cos(90^(@)-theta)cos theta)/(cot theta)+cos(40^(0)+theta)-sin(50^(@)-theta)+(cos^(2)40^(0)+cos^(2)50^(@))/(sin^(2)40^(0)+sin^(2)50^(@))

Prove that: (cos40^(@)+cos50^(@))/(sin40^(@)+sin50^(@))=1