[" Let "y(x)" be the solution of the differential equal "(x log x)],[(dy)/(dx)+y=2x log x,(x>=1)." Then "y(e)" is equal to "]

Let y(x) be the solution of the differential equaiton : (x log x ) (dy)/(dx) +y=2x log x, (x ge 1) Then y(e) is equal to :

Let y(x) be the solution of the differential equation . (x log x) (dy)/(dx) + y = 2x log x, (x ge 1) . Then y (e) is equal to

Let y(x) be the solution of the differential equation ( x log x) (dy)/(dx) + y = 2x log x, ( x gt 1). then y (e) is equal to :

Let y(x) be the solution of the differential equation (x log x)(dy)/(dx)+y=2x log x,(x>=1) Then y(e) is equal to :(1)e(2)0(3)2(4)2e

Let y(x) be the solution of the differential equation ( x log x) (dy)/(dx) + y = 2x log x, ( x gt 1). then y (e ) is equal to :

The solution of the differential equation y (1 + log x) (dx)/(dy) - x log x = 0 is

The solution of the differential equation y (1 + log x) (dx)/(dy) - x log x = 0 is

Find the general solution of the differential equation x log x*(dy)/(dx)+y=(2)/(x)*log x

Let y = y(x) be the solution of the differential equation x dy/dx+y=xlog_ex,(xgt1)." If " 2y(2)=log_e4-1," then "y(e) is equal to

Let y = y(x) be the solution of the differential equation x dy/dx+y=xlog_ex,(xgt1)." If " 2y(2)=log_e4-1," then "y(e) is equal to