Solubility of compound in water is `18g//100gm` of water and its molecular weight is `60`. Mole fraction of solute is `x times10^(-y)` then `x+y` is

6g .of Urea is dissolved in 90g .of water.The mole fraction of solute is

What will be the molality of solution having 18 g of glucose ( molecular weight = 180 ) dissolved in 500 g of water ?

The molecular formula of anhydrous compound A is 64. in the crystalline state its molecular weight is 100. the number of water molecules of crystallisation in the crystalline state is

Elevation in boiling point was 0.52^(@)C when 6 g of a compound X was dissolved in 100 g of water. Molecular weight of X is ( K_(b) of water is 5.2^(@)C per 100 g of water)

The atomicity of a species is x and its atomic weight is y. The molecular weight of the species is

A solution contains 4 g of NaOH and 16.2 g of water. The mole fraction of solute and solvent are respectively.