Spin only magnetic moment of a compound showing paramagnetism is nearly."54.865*10^(-24) Am^(2) Bohr magneton.How many unpaired electrons are there in the compound?

Spin only magnetic moment of a compound showing paramagnetism is nearly 54.865times10^(-24)Am^(2) Bohr magneton.How many unpaired electrons are there in the compound? (9.27times10^(-24)Am^(2)=1 mu_(B))

Spin only magnetic moment of the compound Hg [C0 (SCN)_(4)] is

Spin only magnetic moment of the compound Hg[Co(SCN)_(4)] is sqrt(x) B.M. The value of 'x' is

A compound of a metal ion M^(X+)(z=24) has a spin only magnetic moment of sqrt(15)B.M. . The number of unpaired electrons in the compound are