The equation of tangent at the point `(3,5)` on the curve `y=2x^2-13` is.

Find the equation of the tangent at the point (x,y) of the curve : (x^(2))/(a^(2))+(y^(2))/(b^(2))=1

Find the equations of the tangent and the normal to the curve y=2x^2-3x-1 at (1,\ -2) at the indicated points

Find the equations of the tangent and the normal to the curve y=x^4-b x^3+13 x^2-10 x+5 at (0,\ 5) at the indicated points

Find the equations of the tangent and the normal to the curve y=x^4-6x^3+13 x^2-10 x+5 at x=1 at the indicated points

Find the equations of the tangent and the normal to the curve y=x^2+4x+1 at x=3 at the indicated points

Find the equations of the tangent and the normal to the curve y = x^(4) - 6x^(3) + 13x^(2) - 10x + 5 at the point (1, 3)

Find the equations of the tangent and the normal to the curve y^2=(x^3)/(4-x) at (2,\ -2) at the indicated points

Find the equation of the tangent and the normal to the curve y = x^(2) + 4x + 1 at the point where x = 3

Find the equation of tangent and normal to the curve y =3x^(2) -x +1 at the point (1,3) on it.

Find the equation of the tangent line to the curve y=x^2-2x+7 which is perpendicular to the line 5y-15 x=13 .