A particle is moving with an acceleration given by, `a=-cos t` ; where time t is in seconds and a is in `m/s ^(2)` . It is given that at t=0, u=0 and x=1 .Find distance travelled by particle from `pi` to `2 pi`.

A particle is moving along the x-axis whose acceleration is given by a= 3x-4 , where x is the location of the particle. At t = 0, the particle is at rest at x = 4//3m . The distance travelled by the particles in 5 s is

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = 1 s will be :

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = t will be :

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :

The velocity 'v' of a particle moving along straight line is given in terms of time t as v=3(t^(2)-t) where t is in seconds and v is in m//s . The distance travelled by particle from t=0 to t=2 seconds is :

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The total distance travelled by the paticle between t=0 to t=1s is

A particle is moving along the x-axis such that s=6t-t^(2) , where s in meters and t is in second. Find the displacement and distance traveled by the particle during time interval t=0 to t=5 s .

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

A particle moves in a circle of radius 20 cm. Its linear speed is given by v = (3t^(2) +5t) where t is in second and v is in m/s. Find the resultant acceleration at t = 1s.

A particle is moving in a straight line under acceleration a=54-18 t . The particle starts from the origin. (a) Sketch the a-t, v-t and s-t graph. (b) Find the distance traveled in the first 9 s. (Acceleration is in m//s^(2) , time is in second)