A block is floation in a liquid as shown in figure. Suppose w= weight of block, p=pressure at bottom of block and F= upthrust on the block. No suppose container starts moving upward with some positive acceleration. The new values are suppose w, p' and F'. Then

In the shown figure the minimum value of F required to move the block A away from the wall is :

A 6 kg block is kept on an inclined rough surface as shown in figure.Find the force F requiredto (a) keep the block stationary. (b) move the block downwards with contact velocity and ( c) move the block upwards with an acceleration 4 m//s^(2) (Take g = 10 m//s^(2))

A 6kg block is kept on an inclined rought surface as shown in figure. Find the force F required to (a) keep the block stationary, (b) move the block downwards with constant velocity and (c ) move the block upwards with on acceleration of 4m//s^(2) . (Take =10m//g^(2))

The maximum value of F which can be applied on the system shown in figure so that both blocks move together with same acceleration is

Two block A and B are arrenged as shown in figure (m_(A) = 5 kg and m_(B) = 10 kg) Find the acceleration of blocks if F = 40 N

Find the maximum value of force F such that the block shown in the figure does not move

A man wants to slide down a block of mass m which is kept on a fixed inclined plane of inclination 30^(@) as shown in the figure .Initially the block is not sliding . To just start sliding the man pushed the block down the inclined with a force F . Now , the block starts accelerating. To move it downwards with conatant speed the man starts pulling the block with same force. Surface are such that ratio of maximum static friction to kinetic friction is 2 Now, answer the following questions. If the man continues pushing the block by force F its acceleration would be

On a table three blocks (including the first block) are placed as shown in the figure. Mass of each block is m and coefficient of friction for each block is mu . A force F is applied on the block so as to move the system. The minimum value of F should be