`int_(-1)^(1)|2x+1|dx=(5)/(2)`

int_(1)^(2)|2x-1|dx

int_(1)^(3)(2x+1)dx

int_(-2)^(-1)(5+x)dx

int_(1)^(3)(2x+5)dx

int_(0)^(1)(1+2x)dx

int_(-1)^(1) (dx) / (x^(2)+2x+5) is equal to

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx

int_(1)^(2) (dx)/(2x+5)=

Evaluate the integrals int_(-1)^(1)1(dx)/(x^(2)+2x+5)