If 1gm hydrogen is converted into "0.993gm" of helium in a thermonuclear Reaction,the energy released in the reaction is `9 lambda times10^(10)J`.Then the value of `lambda` is

1 g of hydrogen is converted into 0.993 g of helium in a thermonuclear reaction. The energy released is.

In nuclear fusion, One gram hydrogen is converted into 0.993 gm . If the efficiency of the generator be 5% , then energy obtained in KWH is

In a thermo-nuclear reaction 1.00xx10^(-3)kg hydrogen is converted into 0.993xx10^(-3)kg helium. (a) Calculate the energy released m joule. (b) If the efficiency of the generator be 5%, calculation the energy in kilowatt hours.

If the coefficient of x in the expansion of prod_(r=1)^(110)(1+rx) is lambda(1+110)(1+10+10^(2)) , then the value of lambda is

In a thermo nuclear reaction 10^(-3)Kg of hydrogen is converted into 0.99xx10^(-3)Kg of helium. If the efficiency of the generator is 50% , the electrical energy generated in KWH is

If A = [(0,1),(-1,0)] and A^2016=lambdaI , then value of lambda is

If lambda "and" mu are the cofactors of 3 and -2 respectively in the determinant |{:(1,0,-2),(3,-1,2),(4,5,6):}| the value of lambda+mu is

Decay constant of a reaction is 1.1 xx 10^(-9)//sec , then the half-life of the reaction is