A concave lens with unequal radii of curvature made of glass `(mu_(g)=1.5)` has a focal length of 40cm. If it is immersed in a liquid of refractive index `mu_(1)=2`, then

A convex lens of glass (mu_(g)=1.45) has focal length f_(g) is air. The lens is immersed in a liquid of refractive index (mu_(g)) 1.3. The ratio of the f_(liquid)//f_(g) is

A biconvex lens of refractive index "1.5" has a focal length of "20cm" in air.Its focal length when immersed in a liquid of refractive index "1.6" will be:

Focal length of a lens in air is f. Refractive index of the lens is mu . Focal length changes to f_(1) if lens is immersed in a liquid of refractive index (mu)/(2) and it becomes f_(2) if the lens is immersed in a liquid of refractive index 2 mu . Then

A double convex thin lens made of the refractive index 1.6 has radii of curvature 15 cm each. The focal length of this lens when immersed in a fluid of refractive index 1.63, is

A double convex thin lens made of the refractive index 1.6 has radii of curvature 15 cm each. What is the focal length (in cm) of this les when immersed in a fluid of refractive index 1.63?