The distance between the circumcentre and orthocenter of a `DeltaABC` is `Rsqrt(1-lambda cos A. cosB.cosC)`, then `lambda=`

The distance between the circumcentre and orthocenter of a Delta ABC is R sqrt(1-lambda cos A*cos B*cos C), then lambda=

Find the distance between the circumcentre and the incentre of the DeltaABC.

What is the Distance between circumcenter and orthocenter?

A triangle are (6,0).(0,6) and (6,6). If distance between circumcentre and orthocenter and distance between circumcentre and centroid are lambda and u unit respectively,then (lambda,u) lies on:

If in a DeltaABC , cos A + 2 cosB+cosC= 2 , then a,b, c are in

The hands of an accurate clock have lengths 3 and 4. The distance between the tips of the hands when the distance is increasing most rapidly is sqrt(lambda) then the value of lambda is

If in DeltaABC, a=4,b=6,c=8 then 2cosA+4cosB+cosC=

The phase difference between two points A and B on a wavefront separated by distance lambda is

In DeltaABC , prove that: (c-bcosA)/(b-ccosA)=(cosB)/(cosC)