The equations x+ky+3z=0,3x+ky-2z=0,2x+3y-4z=0 possess a nontrivial solution then the value of `(2k)/33` is

STATEMENT-1 : The system of equations x + ky + 3z =0, 3x + ky - 2z =0, 2x+3y-z=0, possesses a non-trival solution. then value of k is 31/2 STATEMENT -2 Three linear equations in x, y, z can never have no solution if it is homogeneous, hence exactly two types of possible solution.

If the system of equations x-ky+3z=0, 2x+ky-2z=0 and 3x-4y+2z=0 has non - trivial solutions, then the value of (10y)/(x) is equal to

The system of equations: x+ky+3z=0 , 3x+ky-2z=0 , 2x+3y-4z=0 has non- trivial solution. when k=

If the system of equation x+ky+3z=0,3x+ky-2z=0,2x+3y-4z=0 has non trivial solution, then (xy)/(z^2) =

If system of homogenous equations x+ky-2z=0,2x+y-3z=0 and 4x+2y-kz=0 has non-trivial solution thenthe integral value of k is

If 2ax-2y+3z=0,x+ay+2z=0, and 2+az=0 have a nontrivial solution,find the value of a.

If the system of equations x-ky-z=0 , kx-y-z=0 , x+y-z=0 has a non-zero solution , then possible values of k are :

If the system of equations x-ky-z=0,kx-y-z=0,x+y-z=0 has a nonzero solution,then the possible value of k are -1,2 b.1,2 c.0,1 d.-1,1