A square is inscribed in the circle `x^(2)+y^(2)-6x+8y-103=0` with its sides parallel to the coordinate axes. Then the distance of the vertex of this square which is nearest to the origin is

" A square is inscribed in the circle "x^(2)+y^(2)-2x+4y-93=0" with its sides parallel to the coordinates axes one vertex of the square is "

A square is inscribed in a circle x^(2)+y^(2)-4x-6y+5=0 whose sides are parallel to coordinate axis the vertex of the square is/are

A square is incribed in a circle x^(2)+y^(2)-6x+8y-103=0 such that its sides are parallel to co-ordinate axis then the distance of the nearest vertex to origin,is equal to (A) 13 (B) sqrt(127) (C) sqrt(41) (D) 1

A square is inscribed in the circle x^(2)+y^(2)-2x+8y-8=0 whose diagonals are parallel to axes and a vertex in the first quadrant is A then OA is

a square is inscribed in the circle x^(2)+y^(2)-10x-6y+30=0. One side of the square is parallel to y=x+3, then one vertex of the square is:

A square is inscribed in the circle x^(2)+y^(2)-2x+4y+3=0. Its sides are parallel to the coordinate axes.One vertex of the square is (1+sqrt(2),-2) (b) (1-sqrt(2),-2)(1,-2+sqrt(2))(d) none of these

A square is inscribed in the circle x^(2)+y^(2)-2x+4y-93=0 with its sides parallel to the coordinate axes.The coordinates of its vertices are (-6,-9),(-6,-5),(8,-9),(8,5)(-6,-9),(-6,-5),(8,-9),(8,5)(-6,-9),(-6,5),(8,-9),(8,-5)(-6,-9),(-6,5),(8,-9),(8,-5)