" If proton,electron and a-particle are moving with same kinetic energy then the order of their de-Broglie's wavelength is "

The French physicist Louis de Brogie in 1924 postulated that matter, like radiation, should exhibit a dual behaviour. He proposed the following relationship between the wavelength lambda of a material particle, its linear momentum p and planck constant h. lambda =(h)/(p) = (h)/(mv) The de Broglie relation implies that the wavelength of a particle should decrease as its velocity increase. its also implies that for a given velocity heavier particles should have shorter wavelength than lighter particles. The waves associated with particles in motion are called matter waves or de Broglie waves. These waves differe from the electromagnetic waves as they (i) have lower velocites (ii) have no electrcal and magnetic fields, and (iii) are not emitted by the particle under consideration. The experimental confirmation of the de Brgolie's relation was obtained when Davisson and Germer, in 1927, observed that a beam of electron is diffracted by a nickel crystal. As diffraction is a characterstic property of waves hence the beam of electron behaves as a wave, as proposed by de Broglie If proton, electron and alpha -particle are moving with same kinetic energy then the order of their de-Broglie's wavelength.

Which of thses particles having the same kinetic energy has the largest de Broglie wavelength ?

An electron and a proton have same kinetic energy Ratio of their respective de-Broglie wavelength is about

If particles are moving with same velocity , then maximum de - Broglie wavelength will be for

A proton and an electron have same kinetic energy. Which one has greater de-Broglie wavelength and why ?

A proton, a neutron, an electron and an alpha -particle have same energy. Then their de-Broglie wavelengths compare as