In the figure shown, the blocks A and B are connected with an inextensible string. If the block B is pulled with a velocity of 5 m/s then it is observed that block A moves with 10 m/s. Find the angle theta in (degree) shown in the diagram:

Two blocks are connected by an inextensible string as shown. The pulley is fixed. If block A moves down with speed v, find the velocit of block B at instant.

In the arrangement shown, the pulleys are smooth and the strings are inextensible. The acceleration of block B is :

Two blocks of masses m and M are connected by an inextensible light string . When a constant horizontal force acts on the block of mass M. The tension in the string is

The block A is moving downward with constant velocity v_(0.) Find the velocity of the block B. When the string makes an angle theta with the horizontal

In the figure shown, the lower pulley is free to move in a vertical direction only. Block A is given a uniform velocity u as shown, what is the velocity of block B as a function of angle theta ?

Two blocks are connected by an inextensible light string, the string is passing over smooth, light pulley as shown. Find the acceleration of blocks and tension in the string, reaction in pulley.

In the figure shown the block B moves with , velocity 10 ms^(-1) . The velocity of A in the position shown is

Two blocks of masses m_1 and m_2 are connected as shown in the figure. The acceleration of the block m_2 is :

In the figure shown, a person pulls a light string with a constant speed u=10m//s . The other end of the string is tied to a very small block which moves on a smooth horizontal surface. Find the angle 'theta' when the block 3 leaves the surface . Take g=10m//s^(2).