Let Rolle's theorem is applicable for `f(x)=x^(3)+ax^(2)+beta x+2` where x in[0,2] and the value of c=`(1)/(2)` then `(a+2 beta)` is

Rolle's theorem is not applicable to f(x) = |x| in [ -2,2] because

Rolle's theorem is applicable for the function f(x) = |x-1| in [0,2] .

Verify Rolle's theorem for the function f(x)=x^(3)-3x^(2)+2x in the interval [0,2] .

Verify the Rolle's theorem for f(x)=(x-1)^(2) in [1,2].

If rolle's theorem is applicable to the function f(x)=x^(3)-2x^(2)-3x+7 on the interval [0,k] then k is equal

Rolle's theorem is not applicable to the function f (x) = |x| for -2 le x le 2 becaue

Rolle's theorem is not applicable to the function f(x)=|x|"for"-2 le x le2 becase

Let f(x)=Max .{x^(2),(1-x)^(2),2x(1-x)}wherexin[0,1] If Rolle's theorem is applicable for f(x) on largestpossible interval [a,b] then the value of 2(a+b+c) when c in[a,b] such that f(c)=0, is

If Rolle's theorem holds for the function f(x) = 2x^(3) + ax^(2) + bx in the interval [-1,1] for the point c= (1)/(2) , then the value of 2a +b is

If Rolle's theorems applicable to the function f(x)=(ln x)/(x),(x>0) over the interval [a,b] where a in I,b in I, then value of a^(2)+b^(2) can be: