The tangent drawn at `P(t=(pi)/(4))` to the curve `x=sec^(2)t, y=cot t` is

Find the equation of the tangent at t=(pi)/(4) to the curve : x=sin 3t, y = cos 2t.

The equation of the normal at the point t = (pi)/4 to the curve x=2sin(t), y=2cos(t) is :

Find the equation of the tangent and the normal at the point 't,on the curve x=a sin^(3)t,y=b cos^(3)t

Equations of the tangent and normal to the curve x=e^(t) sin t, y=e^(t) cos t at the point t=0 on it are respectively

A unit tangent vector at t=2 on the curve x=t^(2)+2, y=4t-5 and z=2t^(2)-6t is

If OT is the perpendicular drawn from the origin to the tangent at any point t to the curve x = a cos^(3) t, y = a sin^(3) t , then OT is equal to :

The tangent at (t,t^(2)-t^(3)) on the curve y=x^(2)-x^(3) meets the curve again at Q, then abscissa of Q must be

The tangent at A(2,4) on the curve y=x^(3)-2x^(2)+4 cuts the x -axis at T then length of AT is

Find the equations of the tangent and the normal to the curve x y=c^2 at (c t ,\ c//t) at the indicated points.